What was the hardest question on the 2022 Leaving Cert Ordinary Level Paper?
Probably this one. Often you can tell the question that most students found difficult by looking at the marking scheme. This questions got ….5 marks…for both the (i) and the (ii) parts. Students got 3 marks for getting either part (i) or part (ii) correct …and the other 2 marks for getting both parts right.
Why was it tricky for an Ordinary Level student?
1. It’s a graph students wouldn’t be familiar with.
2. We are not given the formula for the function.
3. It has non standard notation u(x) (rather than f(x), h(t) for example).
4. Required to read a maximum point by sight and understand that negative slopes occur where the curve is decreasing.
5. Need to know u'(x) stands for the slope of the function and that u'(4) stands for the slope of the tangent at the point where x=4 (4,2).
6. Need to be able to calculate a slope given a sketch of a line.
Anyway LOADS going on here…for 5 marks. Will post the solution below but worth giving it a go first…whether you are an Ordinary or Higher Level student.